Solving Linear Equations

This article covers solving linear equations. It covers using function machines to solve linear equations and formal setting of solutions.

To grasp a good understanding of linear equations let’s explore the following example;

I am thinking of a number. I multiply it by 3 and then subtract 1 from it. The final answer that I would get is a 14. What number am I thinking of?

The problem is asking to find a number which might seem impossible to find because we know the answer and not how it was formed. The number was multiplied by 3 then 1 was taken away to get 14 as shown below.

With this problem we can work backwards/reverse and undo the entire process as shown below;

Notice above that the signs have been changed to their opposite. You must know that the opposite of subtract is addition and the opposite of multiplication is division. I this problem when we add 1 to 14 and then divide by 3 we get;

In mathematics we use letters to represent unknown numbers. Instead of writing;

“I am thinking of a number and multiply it by 3 and subtracting 1 from it the answer is 14”

We could write;

3 × x – 1 = 14

We can also get rid of the multiplication sign.

In algebra we to avoid using the multiplication sign because the letter x resembles x which is the multiplication sign.

So instead of writing 3 x x we write 3x so we write the problem as;

3x – 1 = 14

Letters to represent unknown numbers

Example: I am thinking of a number and multiply it by 3 and subtracting 1 from it the answer is 14. What is the number?

Answer:

    Explanation:

    To solve the problem we undo the problem as described earlier. Let the number be x. We know that the number x is multiplied by 3 and then 1 is subtracted from it. The answer found is 14. This is very basic to convert into algebra.

    3x – 1 = 14

    We carry through as we did in the previous example. We have to find the value of x. This process is very much similar to rearranging equations by making sure that the value of x is by itself on one side. There 2 basic steps when solving this kind of equation.

    Step 1: First we add 1 to both sides of the equation.
    3x – 1+1 = 14+1

    When you add 1 to both sides you get rid of the 1 from the left hand side of the equation.

    3x = 15
    Step 2: Divide both sides by 3

    The multiplication by 3 has to be undone by dividing both sides by 3.

    3x ÷ 3 = x

    …and…

    15 ÷ 3 = 5

    Therefore dividing both sides by 3 should result;

    3x/3 × 15/3
    x = 5

    Example: Find the value of x in the following equation.

    6x – 3 = 39
    Answer:

    6x – 3+3 = 39+3
    6x/6 x 42/6
    x = 7

    Explanation:

    Step 1: Add 3 to both sides

    Adding 3 to both sides of the equation will make sure that both sides are equal to each other while getting rid of 3 on the left hand side of the equation.

    6x – 3+3 = 39+3
    Step 2: Divide both sides by 6.

    Now divide both sides by 6 to get rid of 6 on the left hand side so that x is left by itself.

    6x/6 x 42/6
    x = 7

    So far we’ve seen that in algebra we avoid multiplication signs because they look like x which is used a lot often. We use x known as variable to represent number/unknown number.
    Example: Find the value of x in the following equation.

    5x + 2 = 32
    Answer:

    5x + 2-2 = 32-2
    5x/5 x 30/5
    x = 6

    Explanation:

    Step 1: Subtract 2 from both sides

    To get rid of 2 from the left hand side of the equation subtract 2 from both sides.

    5x + 2-2 = 32-2
    Step 2: Divide both sides by 5.

    To make sure that x is left alone on one side we divide both sides by 5.

    5x/5 x 30/5
    x = 6

    X on both sides

    Often you may get problems where x or unknown value appears on both sides, for example;

    Example:“I am thinking of a number which I multiply by 6 and add 7. I also get the same answer if I multiply it by 4 and add 19.”

    Answer:

      Explanation:

      We can put the problem into algebra. Let x be the number that we’re trying to find.

      6x + 7 = 4x + 19

      The letter x has been used in the equation to represent unknown values. Again we follow a few basic steps.

      Step 1: Subtract 4x from both sides

      By taking 4x from both sides of the equation we make sure that the term with the letter x appears on one side of the equation.

      2x + 7 = 19
      Step 2: Subtract 7 from both sides

      We must make sure that only x is left on the left hand side of the equation. Therefore we take 7 from both sides;

      2x = 12
      Step 3: Divide both sides by 2

      The term with x has a coefficient of 2. We must get rid of this. To do this we must divide both sides by 2;

      2x/2 = 12/2
      x = 6

      Poof

      We can test each side of the equation in turn to see whether we get the same answer for the x value that we have found. The left hand side of the equation is;.

      6x + 7 = ?

      …and the right hand side of the equation is;.

      4x + 19 = ?

      We can start with the left and see what answer we get when we insert the x values.

      6 × 6 + 7 = 43

      The answer we found for the left hand side of the equation was 43. Now we can try the right hand side as well.

      4 × 6 + 19 = 43

      The answer we get for the right hand side of the equation is also 43 when the found x value is used. Since the answer is the same in both sides that is clear proof that the value of x that we have found is correct.

      6 × 6 + 7 = 4 × 6 + 19

      Example: Find the value of x in the following equation.

      8x + 6 = 11 – 4x
      Answer:

      x = 0.42

      Explanation:

      In this example x appears on both sides of the equation.

      8x + 6 = 11 – 4x

      Again we follow a few basic steps as well divide before.

      Step 1: Add 4x to both sides.

      We need to make sure that the term with x appears alone on one side of the equation. We do this by adding 4x to both sides of the equation.

      8x + 6 + 4x = 11 – 4x + 4x

      The last step made sure that x appeared on the left hand side of the equation.

      12x + 6 = 11
      Step 2: Subtract 6 from both sides

      There is still a term (6) of the left and side which does not contain x, we have to get rid of this. To get rid of 6 from the left hand side we must subtract 6 from both sides of the equation

      12x + 6 – 6 = 11 – 6

      After subtracting 6 from both sides you will get the following expression.

      12x = 5
      Step 3: Divide both sides by 12

      To make sure that the x is left on the left hand side by itself we must divide both sides by 12. This should provide the value of x.

      12x/12 × 5/12
      x = 0.42

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