Deriving (SUVAT) equations of motion

This article explores how to derive the (SUVAT) equations of motion.

The SUVAT equations (equations of linear motion) only work when the acceleration is constant. They will not work for varying acceleration.

They are called ‘SUVAT’ equations because the quantities s, u, v, a, and t are used in the equations where;

  • s = displacement (s)
  • u = initial velocity (ms-1)
  • v = final velocity (ms-1)
  • a = acceleration (ms-2)
  • t = time (s)

A list of the SUVAT equations of motion that you will need to memorise has been given below;

  • v = u + at
  • s = ½(u + v)t
  • s = ut + ½at²
  • v² = u² + 2as

Deriving the (SUVAT) equations of motion

Below we shall derive the SUVAT equations. It can be useful to know how the equations are derived.

v = u + at

Acceleration is defined as the rate of change of velocity over time. This involves final velocityinitial velocity in a given period of time. We can write this as;

Acceleration = Final velocity (v) – Initial velocity (u)/time (t)
a = v – u/t

We can rearrange the expression to get the first SUVAT equation;

at = v – u
v = v + at

s = ½(u + v)t

Velocity is defined as the rate of change of displacement over time. We can find average velocity by adding the initial and final velocities and dividing by 2; this can be written as;

Average velocity = u + v/2

We also know the distance or displacement is equal to velocity x time; (s = vt). So we can replace v with average velocity to get;

s = (u + v/2)t

s = ut + ½at²

From the previous and first equations we derived we know that;

s = ½(u + v)t
v = u + at

We can express displacement in terms of u, a and t rather than u, v, and t. We can substitute v = u + at in the previous equation to get;

s = ½(u + (u + at))t
s = ½(2u + at)²
s = ½(2ut + at²)

…which simplifies to give;

s = ut + ½at²

v² = u² + 2as

This equation was created by ‘Evangelista Torricelli’ to find the velocity of an object moving with a constant acceleration without knowing the time interval. It is therefore known as Torricelli’s equation.

To derive the Torricelli’s equation we shall use the following equations that we have derived above;

v = u + at
s = ½(u + v)t

We can make t the subject in the first equation to get;

t = v – u/a

So now we can replace t in the displacement formulae to get;

s = ½(u + v)(v – u/a)
s = (v + u)(v – u)/2a
2as = (v + u)(v – u)
2as = v² – u²
v² = u² + 2as

Using calculus

We can use calculus to derive the equations of motion. Knowledge of basic calculus is required here. We know that acceleration is the rate of change of velocity over time that is;

dv/dt = a

We know that velocity is the rate of change of displacement over time;

v = ds/dt

That must mean that;

a = ds/dt = d²s/dt²

Integrating a with time should give us an expression for velocity v, this is because acceleration is the rate of change of velocity with time;

v = ds/dt = ∫adt = at + u

Integrating velocity with time should provide an expression for displacement, this is because velocity is the first derivative of displacement modelled as a function of time;

s = ∫ds/dtdt = ∫(at + u)dt = ∫atdt∫udt

…therefore;

s = ut + ½at²

We can use algebraic manipulation to find the other equations;

s = ut + ½at² = ½t(2u + at)
s = ½t(u + u + at) = u² + 2uat + at²
v² = u² + 2a(ut + ½at²) = u² + 2as

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